8. Write the formula for ppm?
_grams of solute_ x 106 = ppm
grams of solution
9. A chemist dissolves 18.91 g of AgNO3 in a 500.0 mL volumetric flask, then adds distilled water to the calibration mark. Determine the molarity of the solution. Show your work.
1) Ag = 107.9 3) 500 mL/1000ml = 0.500 L
N = 14.01
O3 = 48.00 4) M = mol/Liters
169.91 g/mol 0.111 mol = 0.223 mol/L
0.500 L
2) 18.91/169.91 = 0.111 mol AgNO3
- In #9, which is the solvent? Which is the solute?
solvent: distilled water solute: AgNO3
- If you add a tablespoon of NaCl to water, what will it do the boiling temperature?
What will it do the freezing temperature of the solution?
Boiling point raises
Freezing point lowers
- You have 255 mL of a 3.02 M KCl solution. You add 375 mL of water. What is the new molarity of the solution? Show your work.
V2 = 255 mL V1 = 255 mL + 375 mL = 630. mL
M2 = 3.02 mol/L KCl M1 = ?
M1 = V2M2 = 255 mL x 3.02 mol/L = 1.22 mol/L
V1 630. mL
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